$0.1$ mol of the following given antiviral compound $(P)$ will weigh $......... \times 10^{-1} \ g$
$Given :$ molar mass in $g \ mol^{-1} H: 1, C: 12, N: 14, O: 16, F: 19, I: 127$

Assuming chlorine element has two isotopes as $Cl^{35}$ and $Cl^{37}$ with their percentage abundance as $25\%$ and $75\%$ respectively. Find the average atomic weight.

Suppose two elements $X$ and $Y$ combine to form two compounds $XY_{2}$ and $X_{2}Y_{3}$. If $0.05 \ mol$ of $XY_{2}$ weighs $5 \ g$ while $3.011 \times 10^{23}$ molecules of $X_{2}Y_{3}$ weighs $85 \ g$,then atomic masses of $X$ and $Y$ are respectively :

An element of mass $A_1 \, g$ gives a chloride of mass $A_2 \, g$. Calculate its equivalent mass.

Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:

Isotope	Isotopic molar mass $(g \, mol^{-1})$	Abundance (%)
$^{36}Ar$	$35.96755$	$0.337$
$^{38}Ar$	$37.96272$	$0.063$
$^{40}Ar$	$39.9624$	$99.600$

The mass of $500 \, cm^3$ of a gas at $STP$ is $0.581 \, g$. If the gas is a hydrocarbon,what is the gas?