C_2H_2 xrightarrow{text{dil. } H_2SO_4, HgSO_ | vedclass

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(A) The reaction sequence is as follows:$1$. $C_2H_2$ (acetylene) undergoes hydration in the presence of $	ext{dil. } H_2SO_4$ and $HgSO_4$ to form $

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$CH_4$

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(A) The reaction sequence is as follows:$1$. $C_2H_2$ (acetylene) undergoes hydration in the presence of $	ext{dil. } H_2SO_4$ and $HgSO_4$ to form $A$,which is acetaldehyde $(CH_3CHO)$.$2$. Acetaldehyde $(A)$ on oxidation $([O])$ gives $B$,which is acetic acid $(CH_3COOH)$.$3$. Acetic acid $(B)$ reacts with $NaOH$ to form $C$,which is sodium acetate $(CH_3COONa)$.$4$. Sodium acetate $(C)$ undergoes decarboxylation with soda lime $(NaOH/CaO)$ to form $D$,which is methane $(CH_4)$.

$C_2H_2$ $\xrightarrow{\text{dil. } H_2SO_4, HgSO_4} A$ $\xrightarrow{[O]} B$ $\xrightarrow{NaOH} C$ $\xrightarrow{NaOH/CaO} D$
$[D]$ is -

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$C_2H_2$ $\xrightarrow{\text{dil. } H_2SO_4, HgSO_4} A$ $\xrightarrow{[O]} B$ $\xrightarrow{NaOH} C$ $\xrightarrow{NaOH/CaO} D$ $[D]$ is -