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(C) The target compound $(A)$ is a chiral alkyne. To synthesize it,we need to perform an $S_N2$ reaction between a chiral alkyl halide and a nucleophi

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(C) The target compound $(A)$ is a chiral alkyne. To synthesize it,we need to perform an $S_N2$ reaction between a chiral alkyl halide and a nucleophile. The reaction involves the nucleophilic attack of the acetylide ion on the primary carbon of the alkyl bromide. The stereocenter remains unaffected because the reaction occurs at the terminal primary carbon. The correct approach is to use the chiral alkyl bromide $(S)-2	ext{-bromobutane}$ derivative to maintain the configuration at the chiral center. Option $(C)$ correctly represents the sequence where the chiral center is preserved and the alkyne chain is extended.

Which combination is best for the preparation of the compound $(A)$ shown below?

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An unknown compound $(A)$ has a molecular formula $C_4H_6$. When $(A)$ is treated with excess of $Br_2$, a new substance $(B)$ with formula $C_4H_6Br_4$ is formed. $(A)$ forms a white precipitate with ammoniacal silver nitrate solution. $(A)$ may be:

$H_3C-C \equiv CH$ $\xrightarrow{NaNH_2} A$ $\xrightarrow{CH_3CH_2Br} B$ $\xrightarrow{H_2/Pd, BaSO_4} C$
Identify product $(C)$?

In the following reaction,$Z$ is known as: $CH \equiv CH \xrightarrow{Z} CH_3CHO$

Product $(C)$ is: $Ph-CH=CH_2$ $\xrightarrow[CCl_4]{Br_2} (A)$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH} (B)$ $\xrightarrow[(ii) CH_3-Cl]{(i) NaNH_2} (C)$

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