A 500 kg boat is 9 m long and is floating w | vedclass

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(C) Let the mass of the man be $m = 100 \ kg$ and the mass of the boat be $M = 500 \ kg$. The length of the boat is $L = 9 \ m$.Since there is no exte

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$1.5 \ m$ in the direction opposite to the displacement of the man

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(C) Let the mass of the man be $m = 100 \ kg$ and the mass of the boat be $M = 500 \ kg$. The length of the boat is $L = 9 \ m$.Since there is no external horizontal force acting on the system (man + boat),the center of mass of the system remains stationary.Let $x$ be the displacement of the boat. The man moves a distance $L$ relative to the boat,so his displacement relative to the water is $(L - x)$ in the opposite direction.Using the center of mass conservation principle: $m(L - x) = Mx$.$100(9 - x) = 500x$.$900 - 100x = 500x$.$600x = 900$.$x = \frac{900}{600} = 1.5 \ m$.The boat moves in the direction opposite to the man's motion to keep the center of mass at the same position.

$A$ $500 \ kg$ boat is $9 \ m$ long and is floating without motion on still water. $A$ man of mass $100 \ kg$ is at one end. If he runs to the other end of the boat and stops,the displacement of the boat is:

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