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Class 11Physics10-1.Thermometry, Thermal Expansion and CalorimetryPrinciple of Calorimetry and Water Equivalent
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$4 \text{ g}$ of steam at $100^{\circ} C$ is added to $20 \text{ g}$ of water at $46^{\circ} C$ in a container of negligible mass. Assuming no heat is lost to the surroundings, the mass of water in the container at thermal equilibrium is. (Latent heat of vaporisation $= 540 \text{ cal/g}$, Specific heat of water $= 1 \text{ cal/g}^{\circ} C$):- (in $\text{ g}$)

  • A
    $18$
  • B
    $20$
  • C
    $22$
  • D
    $24$
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Class 11 Questions

Class 11

Physics Questions

Chapter

10-1.Thermometry, Thermal Expansion and Calorimetry

Subtopic

Principle of Calorimetry and Water Equivalent

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