A N^{15}-N^{15} text{DNA} molecule is continu | vedclass

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(B) In the Meselson and Stahl experiment,the semi-conservative replication of $	ext{DNA}$ is observed.Starting with $N^{15}-N^{15}$ (heavy) $	ext{DN

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(B) In the Meselson and Stahl experiment,the semi-conservative replication of $	ext{DNA}$ is observed.Starting with $N^{15}-N^{15}$ (heavy) $	ext{DNA}$,after $n$ generations,the total number of $	ext{DNA}$ molecules is $2^n$.The number of heavy $	ext{DNA}$ molecules $(N^{15}-N^{15})$ remains constant at $2$ after the first generation,but since we start with one molecule,the heavy strand is distributed into two hybrid molecules $(N^{15}-N^{14})$ in the first generation.Specifically,in any generation $n$ (where $n \ge 1$),the number of hybrid $	ext{DNA}$ molecules is always $2$,and the number of light $	ext{DNA}$ molecules $(N^{14}-N^{14})$ is $2^n - 2$.The number of heavy $	ext{DNA}$ molecules $(N^{15}-N^{15})$ becomes $0$ after the first generation because the original heavy strands are separated and paired with light strands.Therefore,in the $4^{	ext{th}}$ generation,the percentage of heavy $	ext{DNA}$ is $0 \%$.

$A$ $N^{15}-N^{15}$ $\text{DNA}$ molecule is continuously replicated in $N^{14}$ medium,then what is the percentage of heavy $\text{DNA}$ in the $4^{\text{th}}$ generation (in $\%$)?

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