$A$ current $2 \ A$ flows through a solenoid of self-inductance $3 \ mH$. The energy stored inside the solenoid is $.... \ mJ$.

If a current of $4 \ A$ produces a magnetic flux of $3 \times 10^{-3} \ Wb$ through a coil of $400$ turns,the energy stored in the coil will be: (in $J$)

If the current of $I$ gives rise to a magnetic flux $\phi$ through a coil having $N$ turns,then the magnetic energy stored in the medium surrounding the coil is

The energy stored in an inductor of self-inductance $L$ henry carrying a current of $I$ ampere is:

The energy stored in a coil of inductance $L$ carrying a steady current $i$ is in the form:

The magnetic energy stored in an inductor of inductance $4\,\mu H$ carrying a current of $2\,A$ is: