The energy stored in an inductor of self-inductance $L$ henry carrying a current of $I$ ampere is:

  • A
    $\frac{1}{2} L^{2} I$
  • B
    $\frac{1}{2} L I^{2}$
  • C
    $L I^{2}$
  • D
    $L^{2} I$

Explore More

Similar Questions

In the figure, the magnetic energy stored in the coil is:

$A$ solenoid of inductance $2 \ H$ carries a current of $1 \ A$. What is the magnetic energy stored in the solenoid (in $J$)?

$A$ coil with resistance $20\, \Omega$ and inductance $5\, H$ is connected to a $100\, V$ battery. The energy stored in the coil will be .... $J$.

Energy stored in a coil of self-inductance $40 \, mH$ carrying a steady current of $2 \, A$ is.....$J$

When a current $I$ flows through a coil,it stores the energy $E_1$ in it. Now the current is reduced to $I/2$,the energy stored in the coil becomes $E_2$. The change in the energy is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo