A coil with resistance 20, Omega and inductan | vedclass

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Question

(B) The current $i$ flowing through the coil in a steady state is given by $i = \frac{E}{R}$.Given $E = 100\, V$ and $R = 20\, \Omega$,we have $i = \f

Vedclass · Accepted Answer

$62.50$

Vedclass · Answer

(B) The current $i$ flowing through the coil in a steady state is given by $i = \frac{E}{R}$.Given $E = 100\, V$ and $R = 20\, \Omega$,we have $i = \frac{100}{20} = 5\, A$.The energy $U$ stored in an inductor is given by the formula $U = \frac{1}{2} L i^2$.Substituting the values $L = 5\, H$ and $i = 5\, A$:$U = \frac{1}{2} 	imes 5 	imes (5)^2 = \frac{1}{2} 	imes 5 	imes 25 = \frac{125}{2} = 62.50\, J$.

$A$ coil with resistance $20\, \Omega$ and inductance $5\, H$ is connected to a $100\, V$ battery. The energy stored in the coil will be .... $J$.

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