The magnetic energy stored in an inductor of inductance $4 \ H$ carrying a current of $1.5 \ A$ is
- A$4.5 \ mJ$
- B$3 \ \mu J$
- C$45 \ \mu J$
- D$4500 \ mJ$
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$A$ $100\, mH$ coil carries a current of $1\, A$. The energy stored in its magnetic field is......$J$.
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