$\sum\limits_{m = 1}^n {{m^2}}$ is equal to

  • A
    $\frac{{m(m + 1)}}{2}$
  • B
    $\frac{{m(m + 1)(2m + 1)}}{6}$
  • C
    $\frac{{n(n + 1)(2n + 1)}}{6}$
  • D
    $\frac{{n(n + 1)}}{2}$

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