$A$ first order reaction is given as $A \rightarrow \text{products}$. Its integrated rate equation is:
- A$k = \frac{2.303}{t} \log \frac{a-x}{a}$
- B$k = \frac{1}{t} \log \frac{a}{a-x}$
- C$k = \frac{2.303}{t} \log \frac{a}{a-x}$
- D$-k = \frac{1}{t} \log \frac{a-x}{a}$
Explore More
Similar Questions
The rate of a first-order reaction is $0.04 \ mol \ L^{-1} \ s^{-1}$ at $10 \ s$ and $0.03 \ mol \ L^{-1} \ s^{-1}$ at $20 \ s$ after the initiation of the reaction. The half-life period of the reaction is ......... $s$. (in $.1$)
In a $1^{st}$ order reaction,$75\%$ of the reactant is consumed in $1.388 \, h$. Find the rate constant of the reaction.
Medium
View SolutionAmong the following statements,the correct statement about the half-life period for a first order reaction is
MediumAIIMS 2018
View SolutionWhat is the value of the rate constant of a first-order reaction if the slope of the graph between $\log_{10} \frac{[A]_0}{[A]_t}$ ($y$-axis) and time ($x$-axis) is $1 \times 10^{-3}$?
$A$ first order reaction is found to have a rate constant,$k = 5.5 \times 10^{-14} \ s^{-1}$. Find the half-life of the reaction.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo