$A$ body is heated to $110^{\circ} C$ and placed in air at $10^{\circ} C$. After $1$ hour,its temperature is $60^{\circ} C$. The additional time required for it to cool to $30^{\circ} C$ is

  • A
    $\left(\frac{\log 2}{\log 5}+1\right)$ hours
  • B
    $\left(\frac{\log 5}{\log 2}\right)$ hours
  • C
    $\left(\frac{\log 5}{\log 2}-1\right)$ hours
  • D
    $\left(\frac{\log 2}{\log 5}\right)$ hours

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