sin ^{-1}left(frac{1}{2}right)+cos ^{-1}left( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) આપણે જાણીએ છીએ કે $\sin ^{-1}\left(\frac{1}{2}\right) = \frac{\pi}{6}$ (અથવા $30^{\circ}$).આપણે જાણીએ છીએ કે $\cos ^{-1}\left(\frac{\sqrt{3}}{2}\r

Vedclass · Accepted Answer

$\pi$

Vedclass · Answer

(B) આપણે જાણીએ છીએ કે $\sin ^{-1}\left(\frac{1}{2}\right) = \frac{\pi}{6}$ (અથવા $30^{\circ}$).આપણે જાણીએ છીએ કે $\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right) = \frac{\pi}{6}$ (અથવા $30^{\circ}$).આપણે જાણીએ છીએ કે $\cot ^{-1}\left(-\frac{1}{\sqrt{3}}\right) = \pi - \cot ^{-1}\left(\frac{1}{\sqrt{3}}\right) = \pi - \frac{\pi}{3} = \frac{2\pi}{3}$ (અથવા $120^{\circ}$).આ કિંમતોનો સરવાળો કરતા:$\frac{\pi}{6} + \frac{\pi}{6} + \frac{2\pi}{3} = \frac{2\pi}{6} + \frac{2\pi}{3} = \frac{\pi}{3} + \frac{2\pi}{3} = \frac{3\pi}{3} = \pi$.

$\sin ^{-1}\left(\frac{1}{2}\right)+\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)+\cot ^{-1}\left(-\frac{1}{\sqrt{3}}\right)=$

Similar Questions

જો $\frac{3x+1}{(x-1)(x+3)}=\frac{A}{x-1}+\frac{B}{x+3}$ હોય,તો $\sin^{-1} \frac{A}{B}$ ની કિંમત શોધો.

$\sin \left[2 \cos ^{-1} \frac{\sqrt{5}}{3}\right]$ નું મૂલ્ય શોધો.

$2 \coth^{-1}(4) + \text{sech}^{-1}\left(\frac{3}{5}\right) = $

$\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)$ નું મુખ્ય મૂલ્ય શોધો.

$\sin ^{-1}\left(-\frac{1}{2}\right)$ નું મુખ્ય મૂલ્ય શોધો.

Vedclass Test Series

Exam Paper Generator

Online Exam Module