left| {begin{array}{*{20}{c}}{a + b}&{a + 2b} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) ધારો કે $\Delta = \left| {\begin{array}{*{20}{c}}{a + b}&{a + 2b}&{a + 3b}\{a + 2b}&{a + 3b}&{a + 4b}\{a + 4b}&{a + 5b}&{a + 6b}\end{array}} i

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) ધારો કે $\Delta = \left| {\begin{array}{*{20}{c}}{a + b}&{a + 2b}&{a + 3b}\{a + 2b}&{a + 3b}&{a + 4b}\{a + 4b}&{a + 5b}&{a + 6b}\end{array}} ight|$.હારની પ્રક્રિયાઓ $R_2 	o R_2 - R_1$ અને $R_3 	o R_3 - R_2$ લાગુ કરતા:$R_2 - R_1 = (a+2b)-(a+b) = b, (a+3b)-(a+2b) = b, (a+4b)-(a+3b) = b$.$R_3 - R_2 = (a+4b)-(a+2b) = 2b, (a+5b)-(a+3b) = 2b, (a+6b)-(a+4b) = 2b$.આમ,$\Delta = \left| {\begin{array}{*{20}{c}}{a + b}&{a + 2b}&{a + 3b}\b&b&b\2b&2b&2b\end{array}} ight|$.અહીં $R_2$ અને $R_3$ પ્રમાણસર હોવાથી (ખાસ કરીને,$R_3 = 2R_2$),નિશ્ચાયકનું મૂલ્ય $0$ થાય છે.વૈકલ્પિક રીતે,$a = 1$ અને $b = 1$ મૂકતા,નિશ્ચાયક $\left| {\begin{array}{*{20}{c}}2&3&4\3&4&5\5&6&7\end{array}} ight| = 2(28-30) - 3(21-25) + 4(18-20) = 2(-2) - 3(-4) + 4(-2) = -4 + 12 - 8 = 0$ મળે છે.

$\left| {\begin{array}{*{20}{c}}{a + b}&{a + 2b}&{a + 3b}\\{a + 2b}&{a + 3b}&{a + 4b}\\{a + 4b}&{a + 5b}&{a + 6b}\end{array}} \right| = $

Similar Questions

$2\,\,\left| {\begin{array}{ccc} 1 & 1 & 1 \\ a & b & c \\ {a^2 - bc} & {b^2 - ac} & {c^2 - ab} \end{array}} \right| = $

$\left| \begin{array}{ccc} a - b & b - c & c - a \\ x - y & y - z & z - x \\ p - q & q - r & r - p \end{array} \right| = $

જો $a, b$ અને $c$ એ $A$.$P$. માં હોય,તો $\left|\begin{array}{lll}x+2 & x+3 & x+a \\ x+4 & x+5 & x+b \\ x+6 & x+7 & x+c\end{array}\right|$ નું મૂલ્ય શું થાય?

જો $\left|\begin{array}{ccc}a^{2} & b c & c^{2}+a c \\ a^{2}+a b & b^{2} & c a \\ a b & b^{2}+b c & c^{2}\end{array}\right|=k a^{2} b^{2} c^{2}$ હોય, તો $k=$

જો $\left| {\begin{array}{*{20}{c}} {a - b}&{b - c}&{c - a} \\ {b - c}&{c - a}&{a - b} \\ {c - a + 1}&{a - b}&{b - c} \end{array}} \right| = 0$,જ્યાં $a, b, c \in R - \{0\}$,તો:

Vedclass Test Series

Exam Paper Generator

Online Exam Module