A mass M moving with velocity V along the x-a | vedclass

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Question

(A) According to the law of conservation of linear momentum,the total momentum before the collision equals the total momentum after the collision.Init

Vedclass · Accepted Answer

$\frac{V}{3} \hat{i} + 2V \hat{j}$

Vedclass · Answer

(A) According to the law of conservation of linear momentum,the total momentum before the collision equals the total momentum after the collision.Initial momentum of mass $M$: $\vec{p}_1 = M V \hat{i}$.Initial momentum of mass $2M$: $\vec{p}_2 = 2M (3V \hat{j}) = 6MV \hat{j}$.Total initial momentum: $\vec{p}_{initial} = M V \hat{i} + 6MV \hat{j}$.After the collision,the masses stick together to form a single body of mass $3M$ moving with velocity $\vec{v}_{final}$.Total final momentum: $\vec{p}_{final} = (M + 2M) \vec{v}_{final} = 3M \vec{v}_{final}$.Equating the two: $3M \vec{v}_{final} = M V \hat{i} + 6MV \hat{j}$.Dividing by $3M$: $\vec{v}_{final} = \frac{V}{3} \hat{i} + 2V \hat{j}$.

$A$ mass $M$ moving with velocity $V$ along the $x$-axis collides and sticks to another mass $2M$ which is moving along the $y$-axis with velocity $3V$. The velocity of the combination after the collision is:

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