A machine gun fires bullets of mass 30 text{ | vedclass

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(C) The force exerted by the machine gun is equal to the rate of change of momentum of the bullets fired.Let $n$ be the number of bullets fired per se

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) The force exerted by the machine gun is equal to the rate of change of momentum of the bullets fired.Let $n$ be the number of bullets fired per second.The mass of each bullet is $m = 30 	ext{ g} = 0.03 	ext{ kg}$.The velocity of each bullet is $v = 1000 	ext{ m/s}$.The force $F$ exerted by the gun is given by the formula:$F = n 	imes m 	imes v$Given $F = 300 	ext{ N}$,$m = 0.03 	ext{ kg}$,and $v = 1000 	ext{ m/s}$.Substituting the values:$300 = n 	imes 0.03 	imes 1000$$300 = n 	imes 30$$n = \frac{300}{30} = 10$Therefore,the man can fire at most $10$ bullets per second.

$A$ machine gun fires bullets of mass $30 \text{ g}$ with a velocity of $1000 \text{ m/s}$. The man holding the gun can exert a maximum force of $300 \text{ N}$ on it. How many bullets can he fire per second at most?

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