A photon has a wavelength of 3 ,nm. Its momen | vedclass

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(C) The momentum $p$ of a photon is given by the formula $p = \frac{h}{\lambda}$.
Given $h = 6.63 	imes 10^{-34} \,Js$ and $\lambda = 3 \,nm = 3 	i

Vedclass · Accepted Answer

$2.21 	imes 10^{-25} \,kg \,m/s; 6.63 	imes 10^{-17} \,J$

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(C) The momentum $p$ of a photon is given by the formula $p = \frac{h}{\lambda}$.
Given $h = 6.63 	imes 10^{-34} \,Js$ and $\lambda = 3 \,nm = 3 	imes 10^{-9} \,m$.
$p = \frac{6.63 	imes 10^{-34}}{3 	imes 10^{-9}} = 2.21 	imes 10^{-25} \,kg \,m/s$.
The energy $E$ of a photon is given by $E = \frac{hc}{\lambda} = pc$.
$E = (2.21 	imes 10^{-25} \,kg \,m/s) 	imes (3 	imes 10^8 \,m/s) = 6.63 	imes 10^{-17} \,J$.

$A$ photon has a wavelength of $3 \,nm$. Its momentum and energy, respectively, will be:
$[h = 6.63 \times 10^{-34} \,Js, c = 3 \times 10^8 \,m/s]$

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$A$ photon has a wavelength of $3 \,nm$. Its momentum and energy, respectively, will be: $[h = 6.63 \times 10^{-34} \,Js, c = 3 \times 10^8 \,m/s]$