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(D) The power $P$ of the laser source is given by the formula $P = n 	imes E$, where $n$ is the number of photons emitted per second and $E$ is the e

Vedclass · Accepted Answer

$2	imes10^{16}$

Vedclass · Answer

(D) The power $P$ of the laser source is given by the formula $P = n 	imes E$, where $n$ is the number of photons emitted per second and $E$ is the energy of a single photon.Energy of one photon is $E = \frac{hc}{\lambda}$.Substituting this into the power equation: $P = \frac{n 	imes hc}{\lambda}$.Given values: $P = 6 \ mW = 6 	imes 10^{-3} \ W$, $\lambda = 663 \ nm = 663 	imes 10^{-9} \ m$, $h = 6.63 	imes 10^{-34} \ J.s$, and $c = 3 	imes 10^{8} \ m/s$.Rearranging for $n$: $n = \frac{P 	imes \lambda}{h 	imes c}$.$n = \frac{6 	imes 10^{-3} 	imes 663 	imes 10^{-9}}{6.63 	imes 10^{-34} 	imes 3 	imes 10^{8}}$.$n = \frac{6 	imes 663 	imes 10^{-12}}{19.89 	imes 10^{-26}}$.$n = \frac{3978 	imes 10^{-12}}{19.89 	imes 10^{-26}} = 200 	imes 10^{14} = 2 	imes 10^{16}$ photons per second.

Number of photons of equal energy emitted per second by a $6 \ mW$ laser source operating at $663 \ nm$ is . . . . . . . (Given: $h=6.63\times10^{-34} \ J.s$ and $c=3\times10^{8} \ m/s$)

Similar Questions

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