A metal surface is illuminated by light of gi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The maximum kinetic energy of photoelectrons is given by Einstein's photoelectric equation: $KE_{	ext{max}} = h(v - v_0)$ ... $(i)$Where $h$ is P

Vedclass · Accepted Answer

Unchanged

Vedclass · Answer

(D) The maximum kinetic energy of photoelectrons is given by Einstein's photoelectric equation: $KE_{	ext{max}} = h(v - v_0)$ ... $(i)$Where $h$ is Planck's constant,$v$ is the frequency of incident radiation,and $v_0$ is the threshold frequency.From equation $(i)$,it is clear that the maximum kinetic energy $(KE_{	ext{max}})$ depends only on the frequency of the incident light and the work function of the metal.It is independent of the intensity of the incident radiation.Therefore,if the intensity is reduced to one-fourth of its original value,the maximum kinetic energy of the emitted photoelectrons remains unchanged.

$A$ metal surface is illuminated by light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value,then the maximum $KE$ of the emitted photoelectrons would be

Similar Questions

In a photoelectric effect experiment,the maximum kinetic energy of emitted photoelectrons is $K_0$. If the frequency of the incident radiation is increased by a factor of $n_1$,the new maximum kinetic energy becomes $n_2K_0$. Find the work function of the metal.

In the photoelectric effect, the stopping potential depends on:

For zero photoelectric current,the stopping potential is:

When a photon of energy $3.8 \,eV$ falls on a metallic surface of work function $2.8 \,eV$,then the kinetic energy of the emitted electrons is .......... $eV$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module