A coil of effective area 3 ,m^2 is placed at | vedclass

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(B) Given: Area $A = 3 \,m^2$, Initial magnetic field $B_1 = 0.05 \,Wb/m^2$, Time $dt = 10 \,s$.The coil is placed at right angles to the field, so th

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$12$

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(B) Given: Area $A = 3 \,m^2$, Initial magnetic field $B_1 = 0.05 \,Wb/m^2$, Time $dt = 10 \,s$.The coil is placed at right angles to the field, so the angle $	heta = 0^\circ$ and $\cos 	heta = 1$.Initial magnetic flux $\phi_1 = B_1 A = 0.05 	imes 3 = 0.15 \,Wb$.The field is decreased to $20 \%$ of its original value, so $B_2 = 0.20 	imes 0.05 = 0.01 \,Wb/m^2$.Final magnetic flux $\phi_2 = B_2 A = 0.01 	imes 3 = 0.03 \,Wb$.The induced e.m.f. is given by Faraday's Law: $|e| = |\frac{d\phi}{dt}| = |\frac{\phi_2 - \phi_1}{dt}|$.$|e| = |\frac{0.03 - 0.15}{10}| = |\frac{-0.12}{10}| = 0.012 \,V$.Converting to millivolts: $0.012 \,V = 12 \,mV$.

$A$ coil of effective area $3 \,m^2$ is placed at right angles to a magnetic field of induction $0.05 \,Wb/m^2$. If the field is decreased to $20 \%$ of its original value in $10 \,s$, the e.m.f. induced in the coil will be: (in $\,mV$)

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