The magnetic flux linked with a coil satisfie | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the magnetic flux $\phi = 4t^2 + 6t + 9 	ext{ Wb}$.According to Faraday's law of electromagnetic induction, the induced emf $\varepsilon$ i

Vedclass · Accepted Answer

$22$

Vedclass · Answer

(A) Given the magnetic flux $\phi = 4t^2 + 6t + 9 	ext{ Wb}$.According to Faraday's law of electromagnetic induction, the induced emf $\varepsilon$ is given by $\varepsilon = -\frac{d\phi}{dt}$.Taking the magnitude, $\varepsilon = \left| \frac{d\phi}{dt} ight|$.Differentiating $\phi$ with respect to $t$:$\frac{d\phi}{dt} = \frac{d}{dt}(4t^2 + 6t + 9) = 8t + 6$.At $t = 2 	ext{ s}$, the induced emf is:$\varepsilon = 8(2) + 6 = 16 + 6 = 22 	ext{ V}$.

The magnetic flux linked with a coil satisfies the relation $\phi = 4t^2 + 6t + 9 \text{ Wb}$, where $t$ is the time in seconds. The emf induced in the coil at $t = 2 \text{ s}$ is (in $\text{ V}$)

Similar Questions

$A$ conducting loop is kept perpendicularly in an increasing magnetic field,as shown in the figure. The direction of the induced current in the loop will be:

Derive the relation between induced charge and change in magnetic flux.

The phenomenon of "Electromagnetic induction" was discovered by which scientist?

If a copper ring is moved quickly towards the south pole of a powerful stationary bar magnet,then:

The magnetic flux through a coil perpendicular to its plane and directed into the paper is varying according to the relation $\phi = 5t^2 + 10t + 5$ milliweber. The $e.m.f.$ induced in the loop after $5 \, s$ is ..... $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module