$A$ metal conductor of length $1 \ m$ rotates vertically about one of its ends at an angular velocity of $5 \ rad/s$. If the horizontal component of the Earth's magnetic field is $0.2 \times 10^{-4} \ T$,then the e.m.f. developed between the two ends of the conductor is:

  • A
    $5 \ \mu V$
  • B
    $50 \ mV$
  • C
    $5 \ mV$
  • D
    $50 \ \mu V$

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