A spherical rubber balloon carries a charge q | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{enclosed}}}{\epsilon_0}$.Here,

Vedclass · Accepted Answer

remains unchanged.

Vedclass · Answer

(B) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{enclosed}}}{\epsilon_0}$.Here,$q_{	ext{enclosed}}$ is the total charge enclosed by the spherical balloon.When the balloon is inflated,its radius increases,but the total charge $q$ on its surface remains constant.Since the enclosed charge $q$ does not change,the total electric flux $\phi$ passing through the surface remains unchanged.

$A$ spherical rubber balloon carries a charge $q$ uniformly distributed over its surface. As the balloon is inflated,the total electric flux coming out of the surface:

Similar Questions

An electric line of force in the $X, Y-$ plane is given by the equation $x^2 + y^2 = 1$. $A$ particle with unit positive charge is initially at rest at the point $(1, 0)$ in the $X, Y-$ plane. The particle:

Gauss's law should be invalid if

Give characteristics of electric field lines.

$A$ Gaussian surface of radius $R$ encloses a charge $Q$. If the radius is doubled,the outward electric flux will...

$A$ charge $Q$ is placed at the center of a closed cube. The flux passing through any one face of the cube will be .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module