$A$ body initially at rest is acted upon by a constant force $F$ for time $t$. The kinetic energy at time $t$ is

Two bodies of masses $1 \,g$ and $4 \,g$ are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is

$A$ ball is thrown vertically upwards with a velocity $v$ and an initial kinetic energy $E$. When it reaches half way to the top of its flight,what are its velocity and kinetic energy respectively?

$A$ particle of mass $m_1$ moves with velocity $v_1$ and another particle of mass $m_2$ moves with velocity $v_2$. Both have the same momentum,but their kinetic energies are $E_1$ and $E_2$ respectively. If $m_1 > m_2$,then:

$A$ particle is dropped from a height $h$. $A$ constant horizontal velocity $u$ is given to the particle. Taking $g$ to be constant everywhere, the kinetic energy $E$ of the particle with respect to time $t$ is correctly shown in:

$A$ boy is rolling a $0.5\, kg$ ball on a frictionless floor with a speed of $20\, ms^{-1}$. The ball gets deflected by an obstacle on the way. After deflection,it moves with $5\%$ of its initial kinetic energy. What is the speed of the ball now? (in $ms^{-1}$)