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(B) For a long straight wire of radius $r$ carrying a steady current $I$ uniformly distributed over its cross-section:$1$. Inside the wire $(x < r)$,t

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$\frac{3}{2}$

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(B) For a long straight wire of radius $r$ carrying a steady current $I$ uniformly distributed over its cross-section:$1$. Inside the wire $(x $2$. At distance $x = \frac{r}{2}$,the magnetic field is $B = \frac{\mu_0 I (r/2)}{2 \pi r^2} = \frac{\mu_0 I}{4 \pi r}$.$3$. Outside the wire $(x > r)$,the magnetic field $B^1$ at a distance $x$ from the axis is given by $B^1 = \frac{\mu_0 I}{2 \pi x}$.$4$. At distance $x = 3r$,the magnetic field is $B^1 = \frac{\mu_0 I}{2 \pi (3r)} = \frac{\mu_0 I}{6 \pi r}$.$5$. The ratio is $\frac{B}{B^1} = \frac{\mu_0 I / 4 \pi r}{\mu_0 I / 6 \pi r} = \frac{6}{4} = \frac{3}{2}$.

$A$ long straight wire of radius $r$ carries a steady current $I$. The current is uniformly distributed over its cross-section. The ratio $\left(\frac{B}{B^1}\right)$ of the magnetic field $B$ and $B^1$ at radial distances $\frac{r}{2}$ and $3r$ respectively,from the axis of the wire is:

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