$A$ charge $q$ moves with velocity $\vec{V}$ through an electric field $\vec{E}$ as well as a magnetic field $\vec{B}$. Then the force acting on it is:

  • A
    $q(\vec{E} \times \vec{V})$
  • B
    $q(\vec{B} \times \vec{V})$
  • C
    $q\vec{E} + q(\vec{V} \times \vec{B})$
  • D
    $q(\vec{V} \times \vec{B})$

Explore More

Similar Questions

$A$ charge $q$ enters a region having electric field $E$ and magnetic field $B$ with velocity $v$. If it continues to move with the same velocity, then which of the following statements is not true?

$A$ charge $q$ is released in the presence of an electric field $(E)$ and a magnetic field $(B)$. After some time,its velocity is $v$. Then:

The Lorentz magnetic force is acting on a particle of charge $q$ moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$. The work done by this force on the charged particle is

$A$ collimated beam of charged and uncharged particles is directed towards a hole marked $P$ on a screen as shown below. If the electric and magnetic fields as indicated below are turned $ON$,which of the following statements is correct?

If the magnetic field is parallel to the positive $y$-axis and the charged particle is moving along the positive $x$-axis (Figure),which way would the Lorentz force be for
$(a)$ an electron (negative charge),
$(b)$ a proton (positive charge).

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo