A collimated beam of charged and uncharged pa | vedclass

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(C) The Lorentz force on a charged particle moving in a combined electric field $E$ and magnetic field $B$ is given by $F = q(E + v 	imes B)$.In the

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only neutral particles will go through $P$

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(C) The Lorentz force on a charged particle moving in a combined electric field $E$ and magnetic field $B$ is given by $F = q(E + v 	imes B)$.In the given diagram,the electric field $E$ is directed downwards. For a positively charged particle moving to the right,the electric force $F_e = qE$ acts downwards.The magnetic field $B$ is directed out of the plane. Using the right-hand rule for the magnetic force $F_m = q(v 	imes B)$,where $v$ is to the right and $B$ is out of the plane,the magnetic force $F_m$ acts downwards.Since both the electric force and the magnetic force act in the same downward direction for a positively charged particle,it will be deflected downwards and will not pass through the hole $P$.For a negatively charged particle,the electric force $F_e = qE$ acts upwards,while the magnetic force $F_m = q(v 	imes B)$ acts upwards. Thus,it will be deflected upwards and will not pass through the hole $P$.Neutral particles experience no force from either the electric or magnetic fields $(F = 0)$ and will continue in a straight line to pass through the hole $P$.Therefore,only neutral particles will go through $P$.

$A$ collimated beam of charged and uncharged particles is directed towards a hole marked $P$ on a screen as shown below. If the electric and magnetic fields as indicated below are turned $ON$,which of the following statements is correct?

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