$A$ bar of iron having magnetic moment $2.4 \text{ Am}^2$ weighs $66 \text{ g}$. If the density of the material of the bar is $7700 \text{ kg/m}^3$,the intensity of magnetisation in $\text{Am}^{-1}$ is
- A$1.4 \times 10^5$
- B$2.8 \times 10^5$
- C$1.4 \times 10^4$
- D$2.8 \times 10^4$
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The relation between total magnetic field $(B)$,magnetic intensity $(H)$,permeability of free space $(\mu_{0})$,and magnetic susceptibility $(\chi)$ is:
If the magnetic susceptibility of a substance is $0.6$, then the ratio of permeability of the substance and permeability of free space is
$A$ material of $0.25 \ cm^2$ cross-sectional area is placed in a magnetic field of strength $(H) 1000 \ Am^{-1}$. Then,the magnetic flux produced is (Susceptibility of material is $313$) (Permeability of free space,$\mu_0 = 4 \pi \times 10^{-7} \ Hm^{-1}$)
$A$ toroid has an average diameter of $2.5\,m$,$400$ turns,and a current of $2\,A$. If the total magnetic field inside the toroid is $10\,T$,what is the intensity of magnetization (in $A/m$)?
MediumAIIMS 2019
View SolutionThe magnetic susceptibility of a material of a rod is $499$. Permeability in vacuum is $4\pi \times 10^{-7} \text{ H/m}$. Absolute permeability of the material of the rod is $....\pi \times 10^{-4} \text{ H/m}$.
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