A unit vector is represented as (0.8 hat{i} + | vedclass

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(D) unit vector has a magnitude of $1$. The magnitude of a vector $\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k}$ is given by $|\vec{A}| = \sqrt{A

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$\sqrt{0.2}$

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(D) unit vector has a magnitude of $1$. The magnitude of a vector $\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k}$ is given by $|\vec{A}| = \sqrt{A_x^2 + A_y^2 + A_z^2}$.Given the vector is $(0.8 \hat{i} + b \hat{j} + 0.4 \hat{k})$,we set its magnitude to $1$:$\sqrt{(0.8)^2 + b^2 + (0.4)^2} = 1$Squaring both sides:$(0.8)^2 + b^2 + (0.4)^2 = 1^2$$0.64 + b^2 + 0.16 = 1$$0.80 + b^2 = 1$$b^2 = 1 - 0.80$$b^2 = 0.2$$b = \sqrt{0.2}$

$A$ unit vector is represented as $(0.8 \hat{i} + b \hat{j} + 0.4 \hat{k})$. Hence,the value of $b$ must be:

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