A body covers half of its distance with speed | vedclass

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Question

(A) Let the total distance covered by the body be $2d$.Then,the first half distance is $d$ and the second half distance is $d$.Time taken to cover the

Vedclass · Accepted Answer

$\frac{2uv}{u+v}$

Vedclass · Answer

(A) Let the total distance covered by the body be $2d$.Then,the first half distance is $d$ and the second half distance is $d$.Time taken to cover the first half distance at speed $u$ is $t_1 = \frac{d}{u}$.Time taken to cover the second half distance at speed $v$ is $t_2 = \frac{d}{v}$.Average speed is defined as the total distance divided by the total time taken.Average speed $= \frac{	ext{Total Distance}}{	ext{Total Time}} = \frac{2d}{t_1 + t_2} = \frac{2d}{\frac{d}{u} + \frac{d}{v}}$.Simplifying the expression: $\frac{2d}{d(\frac{1}{u} + \frac{1}{v})} = \frac{2}{\frac{u+v}{uv}} = \frac{2uv}{u+v}$.

$A$ body covers half of its distance with speed $u$ and the other half with a speed $v$,the average speed of the body is

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