$A$ body is moving along a circular track of radius $100 \ m$ with velocity $20 \ m/s$. Its tangential acceleration is $3 \ m/s^{2}$,then its resultant acceleration will be (in $m/s^{2}$)

If $\theta$ is the angle between the velocity vector $\vec{v}$ and the acceleration vector $\vec{a}$ of a particle moving on a circular path with decreasing speed,then .........

For a particle in a non-uniform accelerated circular motion:

The acceleration of a train travelling with a speed of $400 \, m/s$ as it goes round a curve of radius $160 \, m$ is:

An object is moving on a circular track of radius $450\, m$. At some instant,the object is moving at $30\, m/s$ and gaining speed at a uniform rate of $2\, m/s^2$. Its acceleration at this instant is nearly .......... $m/s^2$.

$A$ particle moves in the $xy$-plane with velocity $\vec{v} = x \hat{i} + yt \hat{j}$. At $t = \frac{x \sqrt{3}}{y}$,the tangential and normal accelerations are: