$A$ particle moves in $S.H.M.$ such that its acceleration is $a = -px$,where '$x$' is the displacement of the particle from the equilibrium position and '$p$' is a constant. The period of oscillation is

  • A
    $2 \pi \sqrt{p}$
  • B
    $2 \sqrt{\frac{\pi}{p}}$
  • C
    $\frac{2 \pi}{p}$
  • D
    $\frac{2 \pi}{\sqrt{p}}$

Explore More

Similar Questions

The figures correspond to two circular motions. The radius of the circle,the period of revolution,the initial position,and the sense of revolution (i.e.,clockwise or anti-clockwise) are indicated on each figure. Obtain the corresponding simple harmonic motions of the $x$-projection of the radius vector of the revolving particle $P$,in each case.

The displacement of a particle performing linear $S.H.M.$ is given by $y = A \cos[\pi(t + \phi)]$. If at $t = 0$, the displacement is $y = 2 \text{ cm}$ and velocity is $2\pi \text{ cm/s}$, the value of amplitude $A$ in $\text{cm}$ is

The displacement of a particle is represented by the equation $y = \sin^3 \omega t$. The motion is

$A$ particle executes simple harmonic motion with an amplitude '$A$'. The distance travelled by it in one periodic time is

Generation and propagation of sound and electromagnetic waves can be understood by which motion?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo