A convex lens is dipped in a liquid whose ref | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The focal length of a lens is given by the Lens Maker's Formula: $\frac{1}{f} = (\mu_{rel} - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$,wher

Vedclass · Accepted Answer

become infinite

Vedclass · Answer

(C) The focal length of a lens is given by the Lens Maker's Formula: $\frac{1}{f} = (\mu_{rel} - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$,where $\mu_{rel} = \frac{\mu_{lens}}{\mu_{liquid}}$.Given that the refractive index of the liquid is equal to the refractive index of the lens material,we have $\mu_{lens} = \mu_{liquid}$,which implies $\mu_{rel} = 1$.Substituting this into the formula: $\frac{1}{f} = (1 - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) = 0$.Therefore,$\frac{1}{f} = 0$,which means $f = \infty$ (the focal length becomes infinite).

$A$ convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens material. Then its focal length will

Similar Questions

The distance between a real object and its real image formed by a converging lens is $56 \,cm$. The focal length $f$ of the lens is ............

When light rays from the sun fall on a convex lens along a direction parallel to its axis,which of the following statements is true?

The distance $v$ of the real image formed by a convex lens is measured for various object distances $u$. $A$ graph is plotted between $v$ and $u$. Which one of the following graphs is correct?

$A$ convex lens of crown glass $(n = 1.525)$ will behave as a divergent lens if immersed in:

The figure shows a thin lens with centres of curvature $C_1$ and $C_2$. Find its focal length in $cm$. (Take refractive index $\mu = 1.5$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module