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(D) According to Wien's displacement law,the product of the wavelength of maximum intensity $\lambda_{m}$ and the absolute temperature $T$ is a consta

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$\frac{2}{3} \lambda_{m}$

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(D) According to Wien's displacement law,the product of the wavelength of maximum intensity $\lambda_{m}$ and the absolute temperature $T$ is a constant.$\lambda_{m} T = 	ext{constant}$Given:$T_{1} = 2200 \ K$$T_{2} = 3300 \ K$Let the new wavelength be $\lambda_{m}^{\prime}$.Using the relation $\lambda_{m} T_{1} = \lambda_{m}^{\prime} T_{2}$:$\lambda_{m}^{\prime} = \lambda_{m} 	imes \frac{T_{1}}{T_{2}}$$\lambda_{m}^{\prime} = \lambda_{m} 	imes \frac{2200}{3300}$$\lambda_{m}^{\prime} = \frac{2}{3} \lambda_{m}$

$A$ black body has a maximum wavelength $\lambda_{m}$ at a temperature of $2200 \ K$. Its corresponding wavelength at a temperature of $3300 \ K$ will be:

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