The absolute temperatures of two black bodies are $2000 \ K$ and $3000 \ K$ respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be

Ordinary bodies $A$ and $B$ radiate maximum energy at wavelengths differing by $4 \mu m$. The absolute temperature of body $A$ is $3$ times that of body $B$. The wavelength at which body $B$ radiates maximum energy is: (in $\mu m$)

The black body spectrum of an object $O_1$ is such that its radiant intensity (i.e.,intensity per unit wavelength interval) is maximum at a wavelength of $200\,nm$. Another object $O_2$ has the maximum radiant intensity at $600\,nm$. The ratio of power emitted per unit area by source $O_1$ to that of source $O_2$ is

The colour of a shining bright star is an indication of its

The wavelength of maximum energy,released during an atomic explosion,was $2.93 \times 10^{-10} \ m$. Given that the Wien's constant is $2.93 \times 10^{-3} \ m \ K$,the maximum temperature attained must be of the order of

$A$ black body has a maximum wavelength of $\lambda_m$ at a temperature of $2000 \ K$. What will be the maximum wavelength at a temperature of $3000 \ K$?