A simple pendulum has a length of 2 ,m and a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a conical pendulum (bob whirled in a horizontal plane), the forces acting on the bob are the tension $T$ in the string and the gravitational f

Vedclass · Accepted Answer

$\cos^{-1}(0.1)$

Vedclass · Answer

(B) For a conical pendulum (bob whirled in a horizontal plane), the forces acting on the bob are the tension $T$ in the string and the gravitational force $mg$.Resolving the tension $T$ into vertical and horizontal components:$1$. The vertical component $T \cos \phi$ balances the weight of the bob: $T \cos \phi = mg$.$2$. The horizontal component $T \sin \phi$ provides the necessary centripetal force: $T \sin \phi = \frac{mv^{2}}{R}$.Given:Mass $m = 100 \,g = 0.1 \,kg$Tension $T = 10 \,N$Acceleration due to gravity $g = 10 \,m/s^{2}$From the vertical equilibrium equation:$\cos \phi = \frac{mg}{T}$$\cos \phi = \frac{0.1 \,kg 	imes 10 \,m/s^{2}}{10 \,N}$$\cos \phi = \frac{1}{10} = 0.1$Therefore, the angle $\phi = \cos^{-1}(0.1)$.

$A$ simple pendulum has a length of $2 \,m$ and a bob of mass $100 \,g$. It is whirled in a horizontal plane. If the string breaks under a tension of $10 \,N$, what is the angle made by the string with the vertical? $\left(g=10 \,m/s^{2}\right)$

Similar Questions

$A$ body of mass $m$ is moving with speed $V$ along a circular path of radius $r$. Now,the speed is reduced to $\frac{V}{2}$ and the radius is increased to $3r$. For this change,the initial centripetal force needs to be:

$A$ string of length $L$ fixed at one end carries a mass $m$ at the other end. The string makes $3/\pi$ r.p.s. around the vertical axis through the fixed end. The tension in the string is: (in $mL$)

$A$ small disc is placed on the top of a smooth hemisphere of radius $R$. What is the smallest horizontal velocity $v$ that should be given to the disc for it to leave the hemisphere immediately at the top and not slide down it? [There is no friction]

$A$ stone of mass $16 \, kg$ is attached to a string $144 \, m$ long and is whirled in a horizontal circle. The maximum tension the string can withstand is $16 \, N$. The maximum velocity of revolution that can be given to the stone without breaking it will be ....... $m/s$.

$A$ motorcycle is moving on an overbridge of radius $R$. The driver maintains a constant speed $v$. As the motorcycle is ascending on the overbridge,the normal force on it is

Vedclass Test Series

Exam Paper Generator

Online Exam Module