cos A + cos (240^circ + A) + cos (240^circ - | vedclass

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(B) योग-से-गुणनफल सूत्र $\cos(X + Y) + \cos(X - Y) = 2 \cos X \cos Y$ का उपयोग करने पर:$\cos A + \cos(240^\circ + A) + \cos(240^\circ - A)$$= \cos A +

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$0$

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(B) योग-से-गुणनफल सूत्र $\cos(X + Y) + \cos(X - Y) = 2 \cos X \cos Y$ का उपयोग करने पर:$\cos A + \cos(240^\circ + A) + \cos(240^\circ - A)$$= \cos A + 2 \cos 240^\circ \cos A$$= \cos A(1 + 2 \cos 240^\circ)$चूँकि $\cos 240^\circ = \cos(180^\circ + 60^\circ) = -\cos 60^\circ = -\frac{1}{2}$,$= \cos A(1 + 2(-\frac{1}{2}))$$= \cos A(1 - 1)$$= \cos A(0) = 0$.

$\cos A + \cos (240^\circ + A) + \cos (240^\circ - A) = $

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