A galvanometer coil has a resistance of 10 O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given:Resistance of galvanometer $(G)$ = $10 \ \Omega$Full-scale deflection current $(I_g)$ = $3 \ 	ext{mA} = 3 	imes 10^{-3} \ 	ext{A}$Range o

Vedclass · Accepted Answer

$3 	imes 10^{-3}$

Vedclass · Answer

(C) Given:Resistance of galvanometer $(G)$ = $10 \ \Omega$Full-scale deflection current $(I_g)$ = $3 \ 	ext{mA} = 3 	imes 10^{-3} \ 	ext{A}$Range of ammeter $(I)$ = $10 \ 	ext{A}$The formula for shunt resistance $(S)$ required to convert a galvanometer into an ammeter is given by:$S = \frac{I_g \cdot G}{I - I_g}$Substituting the values:$S = \frac{3 	imes 10^{-3} 	imes 10}{10 - 3 	imes 10^{-3}}$Since $3 	imes 10^{-3} = 0.003 \ 	ext{A}$,the denominator is $10 - 0.003 = 9.997 \ 	ext{A}$.$S = \frac{0.03}{9.997} \approx \frac{0.03}{10} = 0.003 \ \Omega$Therefore,$S = 3 	imes 10^{-3} \ \Omega$.

$A$ galvanometer coil has a resistance of $10 \ \Omega$ and the meter shows full-scale deflection for $3 \ \text{mA}$. The value of the shunt required to convert this meter into an ammeter of range $0$ to $10 \ \text{A}$ is . . . . . . $\Omega$.

Similar Questions

By connecting a resistance of $980 \Omega$ in series with a galvanometer, it is converted into a voltmeter of a certain range. When the resistance of $470 \Omega$ is connected in series, the range is halved. The resistance of the galvanometer is (in $\Omega$)

Certain galvanometers have a fixed core made of non-magnetic metallic material. The function of this metallic material is

Explain: "Increasing the current sensitivity may not necessarily increase the voltage sensitivity".

The range of a voltmeter of resistance $G \ \Omega$ is $V$ volt. The resistance required to be connected in series with it in order to convert it into a voltmeter of range $nV$ volt, will be

What is voltage sensitivity? Obtain its equation.

Vedclass Test Series

Exam Paper Generator

Online Exam Module