(C) To find the molarity of the diluted solution,we use the dilution formula: $M_1 \cdot V_1 = M_2 \cdot V_2$Given:$M_1 = 0.5 \ M$$V_1 = 30 \ mL$$V_2

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(C) To find the molarity of the diluted solution,we use the dilution formula: $M_1 \cdot V_1 = M_2 \cdot V_2$Given:$M_1 = 0.5 \ M$$V_1 = 30 \ mL$$V_2 = 500 \ mL$Substituting the values into the formula:$(0.5 \ M) \cdot (30 \ mL) = M_2 \cdot (500 \ mL)$$M_2 = \frac{0.5 \times 30}{500}$$M_2 = \frac{15}{500} = 0.03 \ M$Therefore,the molarity of the diluted solution is $0.03 \ M$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

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$30 \ mL$ of $0.5 \ M$ $NaOH$ is diluted to $500 \ mL$ by adding water. What will be the molarity of the diluted solution (in $M$)?

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A
$0.05$
B
$0.025$
C
$0.03$
D
$0.015$

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$30 \ mL$ of $0.5 \ M$ $NaOH$ is diluted to $500 \ mL$ by adding water. What will be the molarity of the diluted solution (in $M$)?

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