$A$ resistor and a capacitor are connected in series with an $AC$ source. If the potential drop across the capacitor is $5 \,V$ and that across the resistor is $12 \,V$, then the applied voltage is (in $\,V$)

Two resistors are connected in series across a $5\,V\,rms$ source of alternating potential. The potential difference across the $6\,\Omega$ resistor is $3\,V$. If $R$ is replaced by a pure inductor $L$ of such magnitude that the current remains the same,then the potential difference across $L$ is.......$V$.

In the $A$.$C$. circuit shown,keeping switch $K$ closed,if an iron rod is inserted into the coil,the bulb in the circuit:

An induction coil has an impedance of $10 \Omega$. When an $AC$ signal of frequency $1000 \ Hz$ is applied to the coil,the voltage leads the current by $45^\circ$. The inductance of the coil is

$A$ resistor of $300 \Omega$ and an inductor of $\frac{1}{\pi} \text{ H}$ are connected in series with a $20 \text{ V}$,$200 \text{ Hz}$ $AC$ source. What is the phase difference between the current and the voltage?

When a $DC$ voltage of $100 \, V$ is applied to an inductor, a $DC$ current of $5 \, A$ flows through it. When an $AC$ voltage of $200 \, V$ peak value is connected to the inductor, its inductive reactance is found to be $20\sqrt{3} \, \Omega$. The power dissipated in the circuit is . . . . . . $W$.