$A$ step-down transformer reduces the voltage of a transmission line from $2200 \,V$ to $220 \,V$. The power delivered by it is $880 \,W$ and its efficiency is $88 \%$. The input current is

For a transformer,the turns ratio is $3$ and its efficiency is $0.75$. The current flowing in the primary coil is $2 \,A$ and the voltage applied to it is $100 \,V$. Then the voltage and the current flowing in the secondary coil are ... respectively.

An ideal transformer has $100$ turns in the primary and $250$ turns in the secondary. The peak value of the $ac$ input voltage is $28 \, V$. The r.m.s. secondary voltage is nearest to.....$V$

$A$ current of $4 \text{ A}$ is flowing at $230 \text{ V}$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2300 \text{ V}$ and $40\%$ of power is lost, then the current in the secondary will be (in $\text{ A}$)

In an ideal transformer,the turns ratio is $\frac{N_p}{N_S} = \frac{1}{2}$. The ratio $V_s : V_p$ is equal to (the symbols carry their usual meaning):

If the primary coil of a transformer has $100$ turns and the secondary has $200$ turns,then for an input of $220 \ V$ at $10 \ A$,the output current in the step-up transformer will be . . . . . . . (in $A$)