ABC is a triangle with angle A=30^{circ} and | vedclass

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Question

(A) In $	riangle ABC$,$\angle A=30^{\circ}$ and $BC=10 	ext{ cm}$.Let $R$ be the circumradius of $	riangle ABC$.By the sine rule,$\frac{BC}{\sin A}

Vedclass · Accepted Answer

$100 \pi 	ext{ cm}^2$

Vedclass · Answer

(A) In $	riangle ABC$,$\angle A=30^{\circ}$ and $BC=10 	ext{ cm}$.Let $R$ be the circumradius of $	riangle ABC$.By the sine rule,$\frac{BC}{\sin A} = 2R$.Substituting the given values: $\frac{10}{\sin 30^{\circ}} = 2R$.Since $\sin 30^{\circ} = \frac{1}{2}$,we have $\frac{10}{1/2} = 2R$,which implies $20 = 2R$,so $R = 10 	ext{ cm}$.The area of the circumcircle is given by $\pi R^2$.Area $= \pi (10)^2 = 100 \pi 	ext{ cm}^2$.

$ABC$ is a triangle with $\angle A=30^{\circ}$ and $BC=10 \text{ cm}$. The area of the circumcircle of the triangle is

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