lim _{n rightarrow infty} frac{3 cdot 2^{n+1} | vedclass

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Question

(C) લક્ષ $\lim _{n \rightarrow \infty} \frac{3 \cdot 2^{n+1}-4 \cdot 5^{n+1}}{5 \cdot 2^{n}+7 \cdot 5^{n}}$ ની ગણતરી કરવા માટે,અંશ અને છેદને $5^n$ વડે

Vedclass · Accepted Answer

$-\frac{20}{7}$

Vedclass · Answer

(C) લક્ષ $\lim _{n \rightarrow \infty} \frac{3 \cdot 2^{n+1}-4 \cdot 5^{n+1}}{5 \cdot 2^{n}+7 \cdot 5^{n}}$ ની ગણતરી કરવા માટે,અંશ અને છેદને $5^n$ વડે ભાગતા: $\lim _{n \rightarrow \infty} \frac{3 \cdot 2 \cdot 2^{n} - 4 \cdot 5 \cdot 5^{n}}{5 \cdot 2^{n} + 7 \cdot 5^{n}}$ $= \lim _{n \rightarrow \infty} \frac{6 \cdot 2^{n} - 20 \cdot 5^{n}}{5 \cdot 2^{n} + 7 \cdot 5^{n}}$ $5^n$ વડે ભાગતા: $= \lim _{n \rightarrow \infty} \frac{6 \cdot (\frac{2}{5})^{n} - 20}{5 \cdot (\frac{2}{5})^{n} + 7}$ કારણ કે $\lim _{n \rightarrow \infty} (\frac{2}{5})^{n} = 0$,તેથી: $= \frac{6 \cdot 0 - 20}{5 \cdot 0 + 7} = -\frac{20}{7}$

$\lim _{n \rightarrow \infty} \frac{3 \cdot 2^{n+1}-4 \cdot 5^{n+1}}{5 \cdot 2^{n}+7 \cdot 5^{n}}$ ની કિંમત શોધો.

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