$A$ parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge,potential,and capacitance respectively are:

$A$ thin aluminum sheet of negligible thickness is placed between the plates of a parallel plate capacitor. The capacitance of the capacitor:

The capacity of a parallel plate capacitor is $C$. What will be its capacity when the separation between the plates is halved?

The area of each plate of a parallel plate capacitor is $100 \, cm^2$ and the distance between the plates is $1 \, mm$. It is filled with mica of dielectric constant $6$. The radius of the equivalent capacity of the sphere will be.......$m$.

The potential difference between two plates of a parallel plate capacitor is $2V$. As shown in the figure, electrons are placed at point $P$ and $Q$. So,

One plate of a parallel plate capacitor is connected to a spring as shown in the figure. The area of each plate of the capacitor is $A$ and the distance between the plates is $d$,when the battery is not connected and the spring is unstretched. After connecting the battery,in the steady state the distance between the plates is $0.75 d$,then the force constant of the spring is