The area of each plate of a parallel plate ca | vedclass

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(B) The capacitance of a parallel plate capacitor filled with a dielectric is given by $C = \frac{K \varepsilon_0 A}{d}$.For a spherical conductor of

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$4.77$

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(B) The capacitance of a parallel plate capacitor filled with a dielectric is given by $C = \frac{K \varepsilon_0 A}{d}$.For a spherical conductor of radius $r$,the capacitance is $C = 4 \pi \varepsilon_0 r$.Equating the two capacitances: $4 \pi \varepsilon_0 r = \frac{K \varepsilon_0 A}{d}$.Solving for $r$: $r = \frac{KA}{4 \pi d}$.Given: $A = 100 \, cm^2 = 100 	imes 10^{-4} \, m^2 = 10^{-2} \, m^2$,$d = 1 \, mm = 10^{-3} \, m$,and $K = 6$.Substituting the values: $r = \frac{6 	imes 10^{-2}}{4 	imes 3.14 	imes 10^{-3}} = \frac{6 	imes 10}{12.56} = \frac{60}{12.56} \approx 4.77 \, m$.

The area of each plate of a parallel plate capacitor is $100 \, cm^2$ and the distance between the plates is $1 \, mm$. It is filled with mica of dielectric constant $6$. The radius of the equivalent capacity of the sphere will be.......$m$.

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