$A$ proton is projected with a uniform velocity $v$ along the axis of a current-carrying solenoid,then

  • A
    the proton will be accelerated along the axis,
  • B
    the proton path will be circular about the axis,
  • C
    the proton will move along a helical path.
  • D
    the proton will continue to move with velocity $v$ along the axis,

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$A$ charged particle having charge $q$ is moving perpendicularly to a uniform magnetic field with linear speed $v$ on a circular path of radius $R$. The periodic time of revolution of the particle . . . . . . .

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When a positively charged particle enters a uniform magnetic field with uniform velocity, its trajectory can be:
$(1)$ a straight line
$(2)$ a circle
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Two particles of charges $+Q$ and $-Q$ are projected from the same point with a velocity $v$ in a region of uniform magnetic field $B$ such that the velocity vector makes an angle $\theta$ with the magnetic field. Their masses are $M$ and $2M,$ respectively. Then,they will meet again for the first time at a point whose distance from the point of projection is

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Which particles will have the minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?

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