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(D) Given: Initial velocity $\vec{u} = 10 \hat{j} 	ext{ ms}^{-1}$, Acceleration $\vec{a} = 8 \hat{i} + 2 \hat{j} 	ext{ ms}^{-2}$.Using the kinematic

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$24$

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(D) Given: Initial velocity $\vec{u} = 10 \hat{j} 	ext{ ms}^{-1}$, Acceleration $\vec{a} = 8 \hat{i} + 2 \hat{j} 	ext{ ms}^{-2}$.Using the kinematic equation $\vec{s} = \vec{u}t + \frac{1}{2} \vec{a}t^2$:$\vec{s} = (10 \hat{j})t + \frac{1}{2} (8 \hat{i} + 2 \hat{j})t^2$$\vec{s} = (4t^2) \hat{i} + (10t + t^2) \hat{j}$.Comparing the components with $\vec{s} = x \hat{i} + y \hat{j}$, we get $x = 4t^2$ and $y = 10t + t^2$.Given $x = 16 	ext{ m}$, so $4t^2 = 16 \Rightarrow t^2 = 4 \Rightarrow t = 2 	ext{ s}$.Substituting $t = 2 	ext{ s}$ into the expression for $y$:$y = 10(2) + (2)^2 = 20 + 4 = 24 	ext{ m}$.

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