$A$ radioactive element forms its own isotope after $3$ consecutive disintegrations. The particles emitted are

  • A
    $3 \beta$-particles
  • B
    $2 \beta$-particles and $1 \alpha$-particle
  • C
    $2 \beta$-particles and $1 \gamma$-particle
  • D
    $2 \alpha$-particles and $1 \beta$-particle

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Similar Questions

$A$ nuclear reaction is given by ${}_{Z}X^{A} \to {}_{Z+1}Y^{A} + {}_{-1}e^{0} + \bar{\nu}$,which represents:

The rate of disintegration of a radioactive sample can be increased by:

Consider the following two statements:
$A.$ The energy spectrum of $\alpha-$ particles emitted in radioactive decay is discrete.
$B.$ The energy spectrum of $\beta-$ particles emitted in radioactive decay is continuous.

$A$ nucleus with mass number $220$ initially at rest emits an $\alpha$-particle. If the $Q$ value of the reaction is $5.5\, MeV$,calculate the kinetic energy of the $\alpha$-particle in $MeV$.

In $\beta^{-}$ decay, a neutron transforms into a proton within the nucleus according to the equation:
$\text{neutron} \rightarrow \text{proton} + \beta^{-} + x$
In this equation, the particle represented by '$x$' is:

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