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(C) The dispersive power $\omega$ of a prism is given by $\omega = \frac{\delta_{B} - \delta_{R}}{\delta_{y}}$,where $\delta_{B}$ and $\delta_{R}$ are

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$6: 5$

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(C) The dispersive power $\omega$ of a prism is given by $\omega = \frac{\delta_{B} - \delta_{R}}{\delta_{y}}$,where $\delta_{B}$ and $\delta_{R}$ are the deviations for blue and red rays,and $\delta_{y}$ is the mean deviation,calculated as $\delta_{y} = \frac{\delta_{B} + \delta_{R}}{2}$.For the first prism:$\delta_{B1} = 12^{\circ}$,$\delta_{R1} = 8^{\circ}$.$\delta_{y1} = \frac{12^{\circ} + 8^{\circ}}{2} = 10^{\circ}$.$\omega_{1} = \frac{12^{\circ} - 8^{\circ}}{10^{\circ}} = \frac{4}{10} = \frac{2}{5}$.For the second prism:$\delta_{B2} = 14^{\circ}$,$\delta_{R2} = 10^{\circ}$.$\delta_{y2} = \frac{14^{\circ} + 10^{\circ}}{2} = 12^{\circ}$.$\omega_{2} = \frac{14^{\circ} - 10^{\circ}}{12^{\circ}} = \frac{4}{12} = \frac{1}{3}$.The ratio of dispersive powers is $\frac{\omega_{1}}{\omega_{2}} = \frac{2/5}{1/3} = \frac{2}{5} 	imes 3 = \frac{6}{5}$.

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